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Video: Yuav ua li cas koj nrhiav tau qhov sib npaug ntawm lub perpendicular bisector ntawm ib kab segment?
2024 Tus sau: Miles Stephen | [email protected]. Kawg hloov kho: 2023-12-15 23:36
Sau ib qho kev sib npaug rau hauv point- txoj kab nqes form, y - k = m(x - h), txij li cov txoj kab nqes ntawm lub perpendicular bisector anda point (h, k) lub bisector mus txog yog paub. daws qhov point- txoj kab nqes y = mx + b. Faib cov txoj kab nqes tus nqi. Txav tus nqi k mus rau sab xis ntawm qhov sib npaug.
Kuj paub, koj ua li cas thiaj nrhiav tau qhov sib npaug ntawm ib qho kev sib npaug ntawm ob lub ntsiab lus?
A perpendicular bisector yog a kab thatcuts a kab ntu txuas nrog ob ntsiab lus raws nraim ib nrab ntawm 90 degree kaum. Rau nrhiav tus perpendicularbisector ntawm ob ntsiab lus , txhua yam koj yuav tsum ua yog nrhiav lawv midpoint thiab tsis zoo reciprocal, thiab ntsaws cov lus teb rau hauv kev sib npaug rau a kab inslope-intercept form.
Ib yam li ntawd, koj yuav ua li cas thiaj nrhiav tau qhov sib npaug ntawm kab los ntawm ob lub ntsiab lus? Nrhiav tus Kev sib npaug ntawm kab Muab Tias Koj Paub Ob Ntsiab Lus Nws Hla Los ntawm . Cov kev sib npaug ntawm kab feem ntau yog sau li y = mx + b qhov twg m yog txoj kab nqes thiabb yog y-intercept. Yog koj paub ob ntsiab lus tias a kab hla dhau , nplooj ntawv no yuav qhia koj yuav ua li cas nrhiav tus kev sib npaug ntawm kab.
Ib yam li ntawd, koj tuaj yeem nug, ua li cas koj nrhiav tau qhov perpendicular bisector ntawm ib kab segment siv lub compass?
Kab Segment Bisector, Lub kaum sab xis
- Muab lub compass rau ntawm ib kawg ntawm kab ntu.
- Kho lub compass rau me ntsis ntev dua li ib nrab ntawm cov kab ntev.
- Kos arcs saum toj thiab hauv qab kab.
- Khaws tib lub compass dav, kos arcs los ntawm lwm qhov kawg ntawm kab.
- Muab tus pas ntsuas qhov twg arcs hla, thiab kos cov kab.
Yuav ua li cas koj nrhiav tau ib qho kev sib npaug perpendicular?
Ua ntej, muab tso rau kev sib npaug ntawm cov kab uas tau muab rau hauv daim ntawv-kev cuam tshuam los ntawm kev daws rau y. Koj tau txais y = 2 x + 5, yog li theslope yog -2. Perpendicular cov kab muaj qhov sib npaug-reciprocal slopes, yog li txoj kab nqes ntawm txoj kab peb xav tau nrhiav yog 1/2. Plug nyob rau hauv lub point muab rau hauv lub kev sib npaug y = 1/2 x + b thiab daws b, peb tau b = 6.
Pom zoo:
Yuav daws qhov tsis sib npaug ntawm cov kab sib npaug thiab cov kab sib npaug sib npaug li cas?
Kev daws qhov tsis sib npaug ntawm qhov sib npaug yog zoo ib yam li kev daws cov kab sib npaug. Qhov sib txawv tseem ceeb yog koj tig lub cim tsis sib xws thaum faib lossis muab faib los ntawm tus lej tsis zoo. Graphing linear inequalities muaj ob peb qhov sib txawv ntxiv. Qhov uas yog qhov ntxoov ntxoo muaj xws li qhov tseem ceeb uas qhov kev tsis sib xws ntawm cov kab tawm muaj tseeb
Yuav ua li cas koj nrhiav tau qhov sib npaug ntawm ib kab perpendicular mus rau ib tug taw tes?
Ua ntej, muab qhov sib npaug ntawm kab muab rau hauv daim ntawv nqes hav-intercept los ntawm kev daws rau y. Koj tau txais y = 2 x + 5, txoj kab nqes yog -2. Perpendicular kab muaj qhov tsis sib thooj-reciprocal slopes, yog li txoj kab nqes ntawm txoj kab peb xav pom yog 1/2. Txuas lub ntsiab lus muab rau hauv qhov sib npaug y = 1/2x + b thiab daws rau b, peb tau txais b = 6
Yuav ua li cas koj nrhiav tau qhov sib npaug ntawm ib kab uas muab ib tug point thiab ib tug parallel kab?
Qhov sib npaug ntawm kab hauv daim ntawv nqes hav-intercept yog y = 2x + 5. Qhov nqes hav ntawm parallelline yog tib yam: m = 2. Yog li, qhov sib npaug ntawm kab sib npaug yog y = 2x + a. Txhawm rau nrhiav ib qho, peb siv qhov tseeb tias kab yuav tsum dhau los ntawm qhov muab: 5 = (2) ⋅ (− 3) + a
Nws puas yuav ua rau pom qhov sib npaug ntawm kab sib npaug mus rau ib kab thiab los ntawm ib qho taw tes ntawm kab?
Qhov sib npaug ntawm ib kab uas yog parallel lossis perpendicular rau ib kab? Cov lus teb tau: Cov nqes hav ntawm cov kab sib npaug sib npaug. Hloov txoj kab nqes paub thiab cov kev sib koom ua ke ntawm ib qho taw tes ntawm lwm txoj kab rau hauv daim ntawv point-slope kom pom qhov sib npaug ntawm kab sib npaug
Dab tsi yog qhov sib txawv ntawm cov kab lus sib npaug thiab qhov sib npaug sib npaug?
Cov kab lus sib npaug muaj qhov muaj txiaj ntsig zoo ib yam tab sis tau nthuav tawm nyob rau hauv ib hom ntawv sib txawv uas siv cov khoom ntawm cov lej xws li ax + bx = (a + b) x yog cov kab lus sib npaug. nruj me ntsis, lawv tsis yog 'sib npaug', yog li peb yuav tsum siv 3 kab sib luag hauv 'sib npaug' es tsis yog 2 raws li qhia ntawm no