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Video: Yuav ua li cas koj nrhiav tau lub asymptote ntawm ib tug logarithmic sib npaug?
2024 Tus sau: Miles Stephen | [email protected]. Kawg hloov kho: 2023-12-15 23:36
Ntsiab Lus
- Thaum graphed, lub logarithmic muaj nuj nqi zoo ib yam li cov square cag muaj nuj nqi , tab sis nrog ntsug asymptote raws li x mus txog 0 ntawm sab xis.
- Lub ntsiab lus (1, 0) yog nyob ntawm daim duab ntawm txhua tus logarithmic kev ua haujlwm ntawm daim ntawv y = logbx y = l o g b x, qhov twg b yog tus lej tiag tiag.
Tsis tas li ntawd, koj yuav pom qhov sib npaug ntawm kab rov tav asymptote li cas?
Txhawm rau nrhiav kab rov tav asymptotes:
- Yog hais tias qhov degree (qhov loj tshaj plaws exponent) ntawm tus denominator loj dua qhov degree ntawm tus lej, kab rov tav asymptote yog x-axis (y = 0).
- Yog hais tias lub degree ntawm tus zauv loj dua tus denominator, tsis muaj kab rov tav asymptote.
Tom qab, lo lus nug yog, dab tsi yog cov cuab yeej ntawm lub cav? Logarithm ntawm ib yam khoom Nco ntsoov tias lub khoom ntawm exponents thiab logarithms zoo sib xws heev. Nrog exponents, kom muab ob tug lej nrog tib lub hauv paus, koj ntxiv cov exponents. Nrog logarithms , lub logarithm ntawm cov khoom yog qhov sib npaug ntawm cov logarithms.
Ua li no, koj yuav pom cov asymptotes ntawm LN daim duab li cas?
Nrhiav qhov ntsug asymptote ntawm daim duab ntawm f(x) = ln (2 x + 8). Kev daws. Txij li thaum f yog logarithmic muaj nuj nqi, nws daim duab yuav muaj ntsug asymptote qhov twg nws qhov kev sib cav, 2x + 8, yog sib npaug rau xoom: 2x + 8 = 0 2x = −8 x = −4 Yog li, daim duab yuav muaj ntsug asymptote x = -4.
Koj pom cov asymptotes ntawm kev ua haujlwm li cas?
Nrhiav Kab rov tav Asymptotes ntawm Rational Functions
- Yog tias ob qho tib si polynomials yog tib qib, faib cov coefficients ntawm cov ntsiab lus siab tshaj plaws.
- Yog hais tias lub polynomial nyob rau hauv tus lej yog qis dua tus denominator, x-axis (y = 0) yog kab rov tav asymptote.
Pom zoo:
Yuav daws qhov tsis sib npaug ntawm cov kab sib npaug thiab cov kab sib npaug sib npaug li cas?
Kev daws qhov tsis sib npaug ntawm qhov sib npaug yog zoo ib yam li kev daws cov kab sib npaug. Qhov sib txawv tseem ceeb yog koj tig lub cim tsis sib xws thaum faib lossis muab faib los ntawm tus lej tsis zoo. Graphing linear inequalities muaj ob peb qhov sib txawv ntxiv. Qhov uas yog qhov ntxoov ntxoo muaj xws li qhov tseem ceeb uas qhov kev tsis sib xws ntawm cov kab tawm muaj tseeb
Yuav ua li cas koj nrhiav tau qhov sib npaug ntawm kab tangent ntawm ib tug derivative?
1) Nrhiav tus thawj derivative ntawm f(x). 2) Txuas xvalue ntawm qhov taw tes rau hauv f '(x) txhawm rau nrhiav txoj kab nqes ntawm x. 3) Txuas x tus nqi rau f(x) txhawm rau nrhiav y ua haujlwm ntawm qhov taw tes. 4) Muab txoj kab nqes los ntawm kauj ruam 2 thiab taw tes los ntawm kauj ruam 3 siv cov qauv taw tes-qhov nqes hav kom pom qhov sib npaug rau kab tangent
Yuav ua li cas koj nrhiav tau qhov sib npaug ntawm ib kab perpendicular mus rau ib tug taw tes?
Ua ntej, muab qhov sib npaug ntawm kab muab rau hauv daim ntawv nqes hav-intercept los ntawm kev daws rau y. Koj tau txais y = 2 x + 5, txoj kab nqes yog -2. Perpendicular kab muaj qhov tsis sib thooj-reciprocal slopes, yog li txoj kab nqes ntawm txoj kab peb xav pom yog 1/2. Txuas lub ntsiab lus muab rau hauv qhov sib npaug y = 1/2x + b thiab daws rau b, peb tau txais b = 6
Yuav ua li cas koj nrhiav tau qhov sib npaug ntawm ib kab uas muab ib tug point thiab ib tug parallel kab?
Qhov sib npaug ntawm kab hauv daim ntawv nqes hav-intercept yog y = 2x + 5. Qhov nqes hav ntawm parallelline yog tib yam: m = 2. Yog li, qhov sib npaug ntawm kab sib npaug yog y = 2x + a. Txhawm rau nrhiav ib qho, peb siv qhov tseeb tias kab yuav tsum dhau los ntawm qhov muab: 5 = (2) ⋅ (− 3) + a
Yuav ua li cas koj nrhiav tau qhov sib npaug ntawm ib tug hyperbola muab Asymptotes thiab foci?
Siv qhov laj thawj saum toj no, qhov sib npaug ntawm cov asymptotes yog y = ±ab(x−h) + k y = ± a b (x − h) + k. Zoo li hyperbolas nyob nruab nrab ntawm lub hauv paus chiv keeb, hyperbolas nyob nruab nrab ntawm qhov taw tes (h, k) muaj vertices, co-vertices, thiab foci uas cuam tshuam los ntawm kab zauv c2 = a2 + b2 c 2 = a 2 + b 2